2x^2+5y^2=14

Lösung

2 x^{2} + 5 y^{2} = 14

(h, k) = (0, 0), a = 7, b = \frac{14}{5}

Schritte zur Lösung

2 x^{2} + 5 y^{2} = 14

Rewrite

2 x^{2} + 5 y^{2} = 14

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 7 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{14}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = \frac{14}{5}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = \frac{14}{5}

\frac{( x - 5 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{36} = 1

\frac{( x - 0 ) ^{2}}{36} + \frac{( y - 0 ) ^{2}}{20} = 1

49 x^{2} + 4 y^{2} - 196 = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{16} = 1

(2 x - y) (3 x - y) = 6 x 2 - 5 x y + y 2