(x^2)/(2.48^2)+(y^2)/(2.75^2)=1

Lösung

\frac{x ^{2}}{2.4 8 ^{2}} + \frac{y ^{2}}{2.7 5 ^{2}} = 1

(h, k) = (0, 0), a = 2.48, b = 2.75

Schritte zur Lösung

\frac{x ^{2}}{2.4 8 ^{2}} + \frac{y ^{2}}{2.7 5 ^{2}} = 1

Rewrite

\frac{x ^{2}}{2.4 8 ^{2}} + \frac{y ^{2}}{2.7 5 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2.4 8 ^{2}} + \frac{( y - 0 ) ^{2}}{2.7 5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2.48, b = 2.75

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2.75, a = 2.48

x^{2} + 4 y^{2} - 16 y - 1 = - 1

3 x^{2} + 5 y^{2} - 1 = 0

x^{(2)} + 4 y^{(2)} - 10 x - 40 y + 109 = 0

x^{2} + y^{2} + 6 y < 0

4 x^{2} + 9 y^{2} + 12 x - 18 y - \frac{83}{4} = 0