((x-4)^2)/(36)+((y-2)^2)/(20)=1

Lösung

\frac{( x - 4 ) ^{2}}{36} + \frac{( y - 2 ) ^{2}}{20} = 1

(h, k) = (4, 2), a = 6, b = 25

Schritte zur Lösung

\frac{( x - 4 ) ^{2}}{36} + \frac{( y - 2 ) ^{2}}{20} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{36} + \frac{( y - 2 ) ^{2}}{20} = 1

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{6 ^{2}} + \frac{( y - 2 ) ^{2}}{( 2 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, 2), a = 6, b = 25

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (4, 2), a = 6, b = 25

\frac{x ^{2}}{16} + \frac{y ^{2}}{8} = 1

4 x^{2} + 9 y^{2} + 24 x = 0

\frac{x ^{2}}{81} + \frac{y ^{2}}{25} = 1

\frac{x ^{2} - 2 x + y ^{2}}{4 - y} < 14

10 x^{2} + 6 y^{2} - 60 = 0