(x^2)/(12)+(y^2)/(25)=1

Lösung

\frac{x ^{2}}{12} + \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 23, b = 5

Schritte zur Lösung

\frac{x ^{2}}{12} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{12} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 23, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 23

1 x^{2} + 3 y^{2} + 10 x + 10 y - 11 = 0

16 x^{2} - 160 x + 25 y^{2} + 350 y - 1225 = 0

9 x^{2} + 16 y^{2} - 18 x - 64 y = 71

21 y^{2} + 210 y + 25 x^{2} - 100 x = 0

(\frac{x - 1}{2})^{2} + (y + 3)^{2} = \frac{49}{64}