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Beliebt Geometry >

7(x-2004)^2=23-y^2

Lösung

7 (x - 2004)^{2} = 23 - y^{2}

Lösung

(h, k) = (2004, 0), a = \frac{23}{7}, b = 23

Schritte zur Lösung

7 (x - 2004)^{2} = 23 - y^{2}

Rewrite

7 (x - 2004)^{2} - 23 + y^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 2004 ) ^{2}}{( \frac{23}{7} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 23 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2004, 0), a = \frac{23}{7}, b = 23

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2004, 0), b = 23, a = \frac{23}{7}

Graph

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