8x^2+16y^2=1

Lösung

8 x^{2} + 16 y^{2} = 1

(h, k) = (0, 0), a = \frac{1}{2 2}, b = \frac{1}{4}

Schritte zur Lösung

8 x^{2} + 16 y^{2} = 1

Rewrite

8 x^{2} + 16 y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{2 2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{4} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{1}{2 2}, b = \frac{1}{4}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{1}{2 2}, b = \frac{1}{4}

4 x^{2} + 9 y^{2} \leq 36

x^{2} + 6 x + 9 + y^{2} = 28.09 + \frac{9 x ^{2}}{16}

\frac{( x + 2 ) ^{2}}{36} + \frac{( y - 3 ) ^{2}}{9} = 1

- x^{2} - \frac{y ^{2}}{4} = - 1

x^{2} + 4 y^{2} - 2 x + 16 y + 1 = 0