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Beliebt Geometry >

((x-4)^2)/(16)+((y+2)^2)/(36)=1

Lösung

\frac{( x - 4 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{36} = 1

Lösung

(h, k) = (4, - 2), a = 4, b = 6

Schritte zur Lösung

\frac{( x - 4 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{4 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, - 2), a = 4, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (4, - 2), b = 6, a = 4

Graph

Beliebte Beispiele

y=(2x-4)/(-2y+4)x+6

y = \frac{2 x - 4}{- 2 y + 4} x + 6

x^2+4y^2+9x+10y-14=0

x^{2} + 4 y^{2} + 9 x + 10 y - 14 = 0

((x+1)^2)/4+((y-3/2)^2)/8 =1

\frac{( x + 1 ) ^{2}}{4} + \frac{( y - \frac{3}{2} ) ^{2}}{8} = 1

((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1

\frac{( x - 2 ) ^{2}}{4 ^{2}} + \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

25x^2+9y^2-25=0

25 x^{2} + 9 y^{2} - 25 = 0