x+4-y^2>0

Lösung

x + 4 - y^{2} > 0

(h, k) = (- 4, 0), p = \frac{1}{4}

Schritte zur Lösung

x + 4 - y^{2} > 0

Rewrite

x + 4 - y^{2} > 0

in the standard form:

4 \cdot \frac{1}{4} (x - (- 4)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 0), p = \frac{1}{4}

x^{2} - 8 x - 10 y - 34 = 0

x^{2} + 4 x - 8 y + 12 = 0

x^{2} + y = 3

y^{2} = 2 (1) x

(y - 3)^{2} = 12 (x + 2)