-x+3y^2-6y=4

Lösung

- x + 3 y^{2} - 6 y = 4

(h, k) = (- 7, 1), p = \frac{1}{12}

Schritte zur Lösung

- x + 3 y^{2} - 6 y = 4

Rewrite

- x + 3 y^{2} - 6 y = 4

in the standard form

4 \cdot \frac{1}{12} (x - (- 7)) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- 7, 1), p = \frac{1}{12}

y^{2} - x = 9

y = 8 x^{2} + 4 x - 1

100 = \frac{9 \cdot 1 0 ^{9} \cdot x \cdot x}{y}

y^{2} - 3 = x

4 y^{2} + 8 x - 12 y - 7 = 0