x=8y^2-16y+1

Lösung

x = 8 y^{2} - 16 y + 1

(h, k) = (- 7, 1), p = \frac{1}{32}

Schritte zur Lösung

x = 8 y^{2} - 16 y + 1

Rewrite

x = 8 y^{2} - 16 y + 1

in the standard form

4 \cdot \frac{1}{32} (x - (- 7)) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- 7, 1), p = \frac{1}{32}

1 - f (x) = x^{2} - 6 x + 10

3 x^{2} - 9 y = 0

2 f (x) = 3 x^{2} - x + 2

x^{2} - 6 x + y = 0

x^{2} + (y - 5) 2 = 16