x^{-1}=y^{-2}

Lösung

x^{- 1} = y^{- 2}

(h, k) = (0, 0), p = \frac{1}{4}

Schritte zur Lösung

x^{- 1} = y^{- 2}

Rewrite

x^{- 1} - y^{- 2} = 0

in the standard form

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

y^{2} = x - 5

y^{2} + 2 x + 1 = 0

(y + 1)^{2} = \frac{1}{2} (x - 6)

y - x^{2} + 2 = 0

y + x^{2} = 4