exzentrizität (x^2)/(100)+(y^2)/(64)=1

Lösung

exzentrizität

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

\frac{3}{5}

Dezimale

0.6

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 8

= \frac{1 0 ^{2} - 8 ^{2}}{10}

\frac{1 0 ^{2} - 8 ^{2}}{10} = \frac{3}{5}

= \frac{3}{5}

ecce n t r i c i t y 81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

ecce n t r i c i t y 3 x^{2} + y^{2} - 24 x + 39 = 0

ecce n t r i c i t y 9 x^{2} + 16 y^{2} = 144

ecce n t r i c i t y 4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

ecce n t r i c i t y 4 x^{2} - 16 x + 3 y^{2} + 24 y + 52 = 0