exzentrizität ((x-1)^2)/6+((y-3)^2)/2 =1

Lösung

exzentrizität

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

\frac{2}{3}

Dezimale

0.81649 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1 :

Ellipse with center

(h, k) = (1, 3), a = 6, b = 2

= \frac{( 6 ) ^{2} - ( 2 ) ^{2}}{6}

\frac{( 6 ) ^{2} - ( 2 ) ^{2}}{6} = \frac{2}{3}

= \frac{2}{3}

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

ecce n t r i c i t y 10 x^{2} + 5 y^{2} = 50

ecce n t r i c i t y \frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

ecce n t r i c i t y 4 x^{2} + 9 y^{2} - 16 x + 18 y = 11