x=y^2-2y+1

Lösung

x = y^{2} - 2 y + 1

(h, k) = (0, 1), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} - 2 y + 1

Rewrite

x = y^{2} - 2 y + 1

in the standard form

4 \cdot \frac{1}{4} (x - 0) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (0, 1), p = \frac{1}{4}

x^{2} + y = 8

x^{2} + y = 6

y - 1 = (x - 2)^{2}

- 8 y = x^{2} + 8 x - 8

(y - 3)^{2} = 8 (x - 4)