exzentrizität (x^2)/(2^2)+(y^2)/(9^2)=1

Lösung

exzentrizität

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1

\frac{77}{9}

Dezimale

0.97499 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 2

= \frac{9 ^{2} - 2 ^{2}}{9}

\frac{9 ^{2} - 2 ^{2}}{9} = \frac{77}{9}

= \frac{77}{9}

ecce n t r i c i t y 25 x^{2} + 9 y^{2} - 150 x - 18 y + 9 = 0

ecce n t r i c i t y \frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

ecce n t r i c i t y \frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{3} = 1

ecce n t r i c i t y 9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

ecce n t r i c i t y 4 x^{2} + 25 y^{2} - 40 x + 150 y + 225 = 0