(x-2)^2=4y(y+2)

解答

(x - 2)^{2} = 4 y (y + 2)

(h, k) = (2, - 1), a = 1, b = 2

求解步骤

(x - 2)^{2} = 4 y (y + 2)

将

(x - 2)^{2} - 4 y (y + 2) = 0

改写为标准双曲线方程形式

\frac{( y - ( - 1 ) ) ^{2}}{1 ^{2}} - \frac{( x - 2 ) ^{2}}{2 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (2, - 1), a = 1, b = 2

10 y^{2} - 5 x^{2} = 50

y^{2} - 3 x^{2} - 4 x - 1 = 0

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

\frac{x ^{2}}{8} - \frac{y ^{2}}{6} = 1

2 x^{2} - 4 y^{2} + 9 x - 15 y - 18 = 0