z^2=(y+5)/9+5+y*(y+5)/9

解

z^{2} = \frac{y + 5}{9} + 5 + y \cdot \frac{y + 5}{9}

(h, k) = (0, - 3), a = \frac{41}{3}, b = 41

解答ステップ

z^{2} = \frac{y + 5}{9} + 5 + y \frac{y + 5}{9}

z^{2} - \frac{y + 5}{9} - 5 - y \frac{y + 5}{9} = 0

を標準的な双曲線のequationで書き換える

\frac{( z - 0 ) ^{2}}{( \frac{41}{3} ) ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{( 41 ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (0, - 3), a = \frac{41}{3}, b = 41