3x^2-6x+4-y=0

Lösung

3 x^{2} - 6 x + 4 - y = 0

(h, k) = (1, 1), p = \frac{1}{12}

Schritte zur Lösung

3 x^{2} - 6 x + 4 - y = 0

Rewrite

3 x^{2} - 6 x + 4 - y = 0

in the standard form

4 \cdot \frac{1}{12} (y - 1) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = \frac{1}{12}

x = - y^{2} + 8 y - 14

x^{2} + 8 s + 25 = 0

x^{2} = 40 y

(x + 3)^{2} = 9 (y - 6)

x^{2} - 10 x - 20 y = - 25 - 20