(x^2)/(16)-(y^2)/(75.9)=1

解答

\frac{x ^{2}}{16} - \frac{y ^{2}}{75.9} = 1

(h, k) = (0, 0), a = 4, b = 75.9

求解步骤

\frac{x ^{2}}{16} - \frac{y ^{2}}{75.9} = 1

将

\frac{x ^{2}}{16} - \frac{y ^{2}}{75.9} = 1

改写为标准双曲线方程形式

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{( 75.9 ) ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 4, b = 75.9

3 x^{2} - 2 y^{2} - 6 x + 7 y + 7 = 0

(x - (- 2))^{2} - (y - (- 5))^{2} = (12)^{2}

3 - 4 x + x^{2} - y^{2} \geq 0

y^{2} - 16 x^{2} - 8 y - 96 x - 144 = 0

- \frac{( x + 2 ) ^{2}}{4} + 5 y^{2} = 1