x=y^2+y-1

Lösung

x = y^{2} + y - 1

(h, k) = (- \frac{5}{4}, - \frac{1}{2}), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} + y - 1

Rewrite

x = y^{2} + y - 1

in the standard form

4 \cdot \frac{1}{4} (x - (- \frac{5}{4})) = (y - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{4}, - \frac{1}{2}), p = \frac{1}{4}

(x + 3)^{2} = - 6 (y - 5)

x = 4 - z^{2}

x = - \frac{1}{2} y^{2}

(y - 3)^{2} = - 4 (x - 2)

y^{2} = 36 x