(u-7)^2=2y^2-18y+28

解

(u - 7)^{2} = 2 y^{2} - 18 y + 28

(h, k) = (7, \frac{9}{2}), a = \frac{5}{2}, b = \frac{5}{2}

解答ステップ

(u - 7)^{2} = 2 y^{2} - 18 y + 28

(u - 7)^{2} - 2 y^{2} + 18 y - 28 = 0

を標準的な双曲線のequationで書き換える

\frac{( y - \frac{9}{2} ) ^{2}}{( \frac{5}{2} ) ^{2}} - \frac{( u - 7 ) ^{2}}{( \frac{5}{2} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (7, \frac{9}{2}), a = \frac{5}{2}, b = \frac{5}{2}