4x^2-7p(x)=-3

Lösung

4 x^{2} - 7 p (x) = - 3

(h, k) = (0, \frac{3}{7}), p = \frac{7}{16}

Schritte zur Lösung

4 x^{2} - 7 y = - 3

Rewrite

4 x^{2} - 7 y = - 3

in the standard form:

4 \cdot \frac{7}{16} (y - \frac{3}{7}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{3}{7}), p = \frac{7}{16}

y^{2} = 2 (\frac{1}{2}) x

(x - 9)^{2} = - 16 (y - 6)

x + y^{2} - 2 x - 4 y - 5 = 0

y^{2} = - 4 a x

x^{2} - 4 x + y + 10 = 0