焦点 ((x-3)^2}{16}-\frac{(y+4)^2)/1 =1

解答

焦点

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 4 ) ^{2}}{1} = 1

(3 + 17, - 4), (3 - 17, - 4)

求解步骤

(h + c, k), (h - c, k)

计算双曲线性质

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 4 ) ^{2}}{1} = 1 :

左右开口双曲线，

(h, k) = (3, - 4), a = 4, b = 1

(3 + c, - 4), (3 - c, - 4)

计算

c :

c = 4^{2} + 1^{2} : 17

(3 + 17, - 4), (3 - 17, - 4)