焦点 16x^2-y^2-96x-6y+119=0

解答

焦点

16 x^{2} - y^{2} - 96 x - 6 y + 119 = 0

(3 + 17, - 3), (3 - 17, - 3)

求解步骤

(h + c, k), (h - c, k)

计算双曲线性质

16 x^{2} - y^{2} - 96 x - 6 y + 119 = 0 :

左右开口双曲线，

(h, k) = (3, - 3), a = 1, b = 4

(3 + c, - 3), (3 - c, - 3)

计算

c :

c = 1^{2} + 4^{2} : 17

(3 + 17, - 3), (3 - 17, - 3)