焦点 ((x-3)^2}{13}-\frac{(y-5)^2)/7 =1

解答

焦点

\frac{( x - 3 ) ^{2}}{13} - \frac{( y - 5 ) ^{2}}{7} = 1

(3 + 25, 5), (3 - 25, 5)

求解步骤

(h + c, k), (h - c, k)

计算双曲线性质

\frac{( x - 3 ) ^{2}}{13} - \frac{( y - 5 ) ^{2}}{7} = 1 :

左右开口双曲线，

(h, k) = (3, 5), a = 13, b = 7

(3 + c, 5), (3 - c, 5)

计算

c :

c = 13^{2} + 7^{2} : 25

(3 + 25, 5), (3 - 25, 5)