y<=-1/4 (x+6)^2+2

Lösung

y \leq - \frac{1}{4} (x + 6)^{2} + 2

(h, k) = (- 6, 2), p = - 1

Schritte zur Lösung

y \leq - \frac{1}{4} (x + 6)^{2} + 2

Rewrite

y \leq - \frac{1}{4} (x + 6)^{2} + 2

in the standard form:

4 (- 1) (y - 2) = (x - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 6, 2), p = - 1

x^{2} + 8 x + 4 y + 20 = 0

y > x^{2} + 3 x

3 x^{2} - y = 5

x^{2} + 4 x - 24 y - 92 = 0

y \leq x^{2} - 1