asymptoten+(x^2}{16}-\frac{y^2)/9 =1

Lösung

asymptoten

+ \frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

Schritte zur Lösung

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

+ \frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

y = \frac{3}{4} (x - 0) + 0, y = - \frac{3}{4} (x - 0) + 0

Fasse zusammen

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

a sy m pt o t es 9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

a sy m pt o t es \frac{y ^{2}}{64} - \frac{x ^{2}}{81} = 1

a sy m pt o t es \frac{( y - 2 ) ^{2}}{9} - (x + 2)^{2} = 1

a sy m pt o t es 2 x^{2} - 3 y^{2} = 6

a sy m pt o t es 6 x^{2} - 36 y^{2} = 2304