center 25y^2-16x^2-400=0

Lösung

center

25 y^{2} - 16 x^{2} - 400 = 0

(0, 0)

Schritte zur Lösung

25 y^{2} - 16 x^{2} - 400 = 0

Rewrite

25 y^{2} - 16 x^{2} - 400 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 5

And the center is:

(0, 0)

ce n t er 9 x^{2} - 16 y^{2} = 144

ce n t er \frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

ce n t er \frac{( x - 2 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{5} = 1

ce n t er + \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

ce n t er 5 x^{2} - 2 y^{2} + 10 x - 12 y = 23