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Beliebt Geometry >

center 9x^2-16y^2-126x+160y-103=0

Lösung

center

9 x^{2} - 16 y^{2} - 126 x + 160 y - 103 = 0

Lösung

(7, 5)

Schritte zur Lösung

9 x^{2} - 16 y^{2} - 126 x + 160 y - 103 = 0

Rewrite

9 x^{2} - 16 y^{2} - 126 x + 160 y - 103 = 0

in the form of a standard hyperbola equation

\frac{( x - 7 ) ^{2}}{4 ^{2}} - \frac{( y - 5 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (7, 5), a = 4, b = 3

And the center is:

(7, 5)

Graph

Beliebte Beispiele

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