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Beliebt Geometry >

center y^2-4y-4x^2+13=0

Lösung

center

y^{2} - 4 y - 4 x^{2} + 13 = 0

Lösung

(0, 2)

Schritte zur Lösung

y^{2} - 4 y - 4 x^{2} + 13 = 0

Rewrite

y^{2} - 4 y - 4 x^{2} + 13 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{3}{2} ) ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 2), a = \frac{3}{2}, b = 3

And the center is:

(0, 2)

Graph

Beliebte Beispiele

center ((y+3)^2)/4-((x+1)^2)/(16)=1

ce n t er \frac{( y + 3 ) ^{2}}{4} - \frac{( x + 1 ) ^{2}}{16} = 1

center ((x-1)^2)/4-((y+3)^2)/(16)=1

ce n t er \frac{( x - 1 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{16} = 1

center x^2-y^2=9

ce n t er x^{2} - y^{2} = 9

center 4y^2-9x^2+16y+18x=29

ce n t er 4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

center 16y^2-32y-9x^2-18x=137

ce n t er 16 y^{2} - 32 y - 9 x^{2} - 18 x = 137