center y^2-4x^2<1

Lösung

center

y^{2} - 4 x^{2} < 1

(0, 0)

Schritte zur Lösung

y^{2} - 4 x^{2} < 1

Rewrite

y^{2} - 4 x^{2} < 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = \frac{1}{2}

And the center is:

(0, 0)

ce n t er - 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36

ce n t er \frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1

ce n t er \frac{( x - 1 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

ce n t er \frac{( y - 1 ) ^{2}}{9} - \frac{( x - 4 ) ^{2}}{25} = 1

ce n t er \frac{( x + 5 ) ^{2}}{\frac{1}{9}} - \frac{( y - 3 ) ^{2}}{\frac{1}{4}} = 1