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Beliebt Geometry >

center 5y^2-16x^2+400=0

Lösung

center

5 y^{2} - 16 x^{2} + 400 = 0

Lösung

(0, 0)

Schritte zur Lösung

5 y^{2} - 16 x^{2} + 400 = 0

Rewrite

5 y^{2} - 16 x^{2} + 400 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 0 ) ^{2}}{( 4 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 45

And the center is:

(0, 0)

Graph

Beliebte Beispiele

center 4x^2-9y^2-16x+18y-7=0

ce n t er 4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

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center 1/144 x^2-1/196 y^2=1

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