center (x^2)/(0.0008)-(y^2)/(0.999)=1

Lösung

center

\frac{x ^{2}}{0.0008} - \frac{y ^{2}}{0.999} = 1

(0, 0)

Schritte zur Lösung

\frac{x ^{2}}{0.0008} - \frac{y ^{2}}{0.999} = 1

Rewrite

\frac{x ^{2}}{0.0008} - \frac{y ^{2}}{0.999} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 0.0008 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 0.999 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 0.0008, b = 0.999

And the center is:

(0, 0)

ce n t er \frac{x ^{2}}{36} - \frac{y ^{2}}{16} = 1

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ce n t er 7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

ce n t er x^{2} - (y - 4)^{2} = 1