exzentrizität (x^2)/(16)-(y^2)/(20)=1

Lösung

exzentrizität

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

\frac{3}{2}

Dezimale

1.5

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 25

= \frac{4 ^{2} + ( 2 5 ) ^{2}}{4}

Fasse zusammen

= \frac{3}{2}

ecce n t r i c i t y 16 x^{2} - 25 y^{2} = 400

ecce n t r i c i t y 16 x^{2} - 9 y^{2} = 144

ecce n t r i c i t y 4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

ecce n t r i c i t y 9 y^{2} - x^{2} + 2 x + 54 y + 62 = 0

ecce n t r i c i t y 4 x^{2} - 25 y^{2} + 100 y = 200