离心率-(x^2)/(a^2)+(y^2)/(b^2)=1

解答

离心率

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{b ^{2} + a ^{2}}{b}

求解步骤

= \frac{a ^{2} + b ^{2}}{a}

计算双曲线性质

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1 :

上下开口双曲线，

(h, k) = (0, 0), a = b, b = a

= \frac{b ^{2} + a ^{2}}{b}

ecce n t r i c i t y \frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

ecce n t r i c i t y \frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

ecce n t r i c i t y \frac{( x + 1 ) ^{2}}{4} - (y - 5)^{2} = 4

ecce n t r i c i t y 9 x^{2} - 16 y^{2} = 144