exzentrizität ((x-2)^2)/9-((y+1)^2)/5 =1

Lösung

exzentrizität

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{5} = 1

\frac{14}{3}

Dezimale

1.24721 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{5} = 1 :

Right-left Hyperbola with

(h, k) = (2, - 1), a = 3, b = 5

= \frac{3 ^{2} + ( 5 ) ^{2}}{3}

Fasse zusammen

= \frac{14}{3}

ecce n t r i c i t y \frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

ecce n t r i c i t y 9 (x - 2)^{2} - 4 y^{2} = 36

ecce n t r i c i t y - \frac{( x - 2 ) ^{2}}{5} + \frac{( y + 1 ) ^{2}}{9} = 1

ecce n t r i c i t y \frac{x ^{2}}{58} - \frac{y ^{2}}{174} = 1

ecce n t r i c i t y \frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1