2x^2+7y=0

Lösung

2 x^{2} + 7 y = 0

(h, k) = (0, 0), p = - \frac{7}{8}

Schritte zur Lösung

2 x^{2} + 7 y = 0

Rewrite

2 x^{2} + 7 y = 0

in the standard form:

4 (- \frac{7}{8}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{7}{8}

(y - 2)^{2} = 4 (x + 6)

C^{2} + 3 C + 5 T = 1300

x^{2} = 0.1 y

2 x^{2} - 5 x + k (x) = 0

2 x + y = x^{2}