2x-y^2=7

Lösung

2 x - y^{2} = 7

(h, k) = (\frac{7}{2}, 0), p = \frac{1}{2}

Schritte zur Lösung

2 x - y^{2} = 7

Rewrite

2 x - y^{2} = 7

in the standard form:

4 \cdot \frac{1}{2} (x - \frac{7}{2}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{2}, 0), p = \frac{1}{2}

x = - \frac{1}{20} y^{2} - \frac{3}{10} y - \frac{69}{20}

4 x^{2} + y = 100

4 x^{2} + 12 x + 48 y = 159

x - y^{2} \leq 2

3 x^{2} = 12 y