x^2-8x-y-4=0

Lösung

x^{2} - 8 x - y - 4 = 0

(h, k) = (4, - 20), p = \frac{1}{4}

Schritte zur Lösung

x^{2} - 8 x - y - 4 = 0

Rewrite

x^{2} - 8 x - y - 4 = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 20)) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, - 20), p = \frac{1}{4}

x \frac{x + 4}{y + 1} = 2

x = 2 y^{2} - y

x = \frac{2 k ( x )}{x + 2}

x + (y + 1)^{2} = 2

y \leq x^{2} + 4 x + 3