y^2-8x-4y-20=0

Lösung

y^{2} - 8 x - 4 y - 20 = 0

(h, k) = (- 3, 2), p = 2

Schritte zur Lösung

y^{2} - 8 x - 4 y - 20 = 0

Rewrite

y^{2} - 8 x - 4 y - 20 = 0

in the standard form

4 \cdot 2 (x - (- 3)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 3, 2), p = 2

8 x^{2} + 3 x - h (x) = 0

x^{2} - 2 x - 4 y + 13 = 4

x^{2} + y - 144 = 0

2 x^{2} - 16 m (x) + 8 = 0

2 x^{2} = - y