x^2=5(y-4)

Lösung

x^{2} = 5 (y - 4)

(h, k) = (0, 4), p = \frac{5}{4}

Schritte zur Lösung

x^{2} = 5 (y - 4)

Rewrite

x^{2} = 5 (y - 4)

in the standard form:

4 \cdot \frac{5}{4} (y - 4) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 4), p = \frac{5}{4}

y^{2} - 3 x - 4 y + 22 = 0

3 x^{2} = - 4 y

1 = \frac{3 x ^{2} + 5 x}{h ( x )}

x - 4 y^{2} \geq 0.2 - x - 7

x^{2} = y - 7