4x=2y^2-4y-23

Lösung

4 x = 2 y^{2} - 4 y - 23

(h, k) = (- \frac{25}{4}, 1), p = \frac{1}{2}

Schritte zur Lösung

4 x = 2 y^{2} - 4 y - 23

Rewrite

4 x = 2 y^{2} - 4 y - 23

in the standard form

4 \cdot \frac{1}{2} (x - (- \frac{25}{4})) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{25}{4}, 1), p = \frac{1}{2}

x = 10 y - 24 - y^{2}

(y - 2)^{2} = 3 (x - 2)

(x - 4)^{2} = 16 (y + 4)

y^{2} + y + 2 = 7 x

9 (x - 1) + 4 y^{2} = 36