4a+7b+3a-2b+2aa=3

解

4 a + 7 b + 3 a - 2 b + 2 aa = 3

(h, k) = (- \frac{7}{4}, \frac{73}{40}), p = - \frac{5}{8}

解答ステップ

4 a + 7 b + 3 a - 2 b + 2 aa = 3

4 a + 7 b + 3 a - 2 b + 2 aa = 3

を標準的な形式で書き換える

4 (- \frac{5}{8}) (b - \frac{73}{40}) = (a - (- \frac{7}{4}))^{2}

ゆえに放物線の特性は:

(h, k) = (- \frac{7}{4}, \frac{73}{40}), p = - \frac{5}{8}