x=sqrt(5)y^2

Lösung

x = 5 y^{2}

(h, k) = (0, 0), p = \frac{1}{4 5}

Schritte zur Lösung

x = 5 y^{2}

Rewrite

x = 5 y^{2}

in the standard form:

4 \cdot \frac{1}{4 5} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4 5}

x^{2} = 11 y

(x + 2)^{2} = - 8 y

(x - 4)^{2} = - 12 (y - 6)

x^{2} - 2 x + 4 y = 15

y^{2} = 4 x - 4