x=2x-y^2

Lösung

x = 2 x - y^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Schritte zur Lösung

x = 2 x - y^{2}

Rewrite

x = 2 x - y^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

(y + 2)^{2} = 16 x

x^{2} - 6 x + y + 5 = 0

x^{2} - k (x) - x = 0

xx - y = 5

y + 2 = \frac{2 x}{3} (x + 2)