2x-y+3x^2=0

Lösung

2 x - y + 3 x^{2} = 0

(h, k) = (- \frac{1}{3}, - \frac{1}{3}), p = \frac{1}{12}

Schritte zur Lösung

2 x - y + 3 x^{2} = 0

Rewrite

2 x - y + 3 x^{2} = 0

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{1}{3})) = (x - (- \frac{1}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, - \frac{1}{3}), p = \frac{1}{12}