yy-320=40(x-2010)

Lösung

yy - 320 = 40 (x - 2010)

(h, k) = (2002, 0), p = 10

Schritte zur Lösung

yy - 320 = 40 (x - 2010)

Rewrite

yy - 320 = 40 (x - 2010)

in the standard form:

4 \cdot 10 (x - 2002) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (2002, 0), p = 10

y^{2} + 4 y + 6 x - 5 = 0

x + 4 > y^{2}

x = a y^{2}

y = 1 (x - 1)^{2} + 0

y^{2} - x - 2 = 0