4x^2-7y=9

Lösung

4 x^{2} - 7 y = 9

(h, k) = (0, - \frac{9}{7}), p = \frac{7}{16}

Schritte zur Lösung

4 x^{2} - 7 y = 9

Rewrite

4 x^{2} - 7 y = 9

in the standard form:

4 \cdot \frac{7}{16} (y - (- \frac{9}{7})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{9}{7}), p = \frac{7}{16}

r^{2} - s = 0

y \frac{y}{204} + \frac{x}{1.265} = 3026

x + y = x^{2}

y^{2} - 6 y - 12 x - 39 = 0

x^{2} - 10 y = 0