4y^2-8y+3x=2

Lösung

4 y^{2} - 8 y + 3 x = 2

(h, k) = (2, 1), p = - \frac{3}{16}

Schritte zur Lösung

4 y^{2} - 8 y + 3 x = 2

Rewrite

4 y^{2} - 8 y + 3 x = 2

in the standard form

4 (- \frac{3}{16}) (x - 2) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (2, 1), p = - \frac{3}{16}

f (x) (x)^{- 1} = \frac{x - 4}{11}

4 x - x^{2} + 2 y = 0

x^{2} + 5 y = 20

x^{2} = x + y

(x + \frac{3}{2})^{2} = 4 (y - 2)