x^{(2)}+2y=0

Lösung

x^{(2)} + 2 y = 0

(h, k) = (0, 0), p = - \frac{1}{2}

Schritte zur Lösung

x^{2} + 2 y = 0

Rewrite

x^{2} + 2 y = 0

in the standard form:

4 (- \frac{1}{2}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{2}

y \frac{y}{12.5} = 3.5 + x

x^{2} - 4 x - y + 8 = 0

x - y^{2} = 6

e x - y^{2} = 5

x - y^{2} > 0